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UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education MARK SCHEME for the May/June 2010 question paper for the guidance of teachers 0607 CAMBRIDGE INTERNATIONAL MATHEMATICS 0607/06 Paper 6 (Extended), maximum raw mark 40 This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of
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    UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education MARK SCHEME for the May/June 2010 question paper for the guidance of teachers 0607 CAMBRIDGE INTERNATIONAL MATHEMATICS   0607/06 Paper 6 (Extended), maximum raw mark 40 This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does notindicate the details of the discussions that took place at an Examiners’ meeting before marking began,which would have considered the acceptability of alternative answers.Mark schemes must be read in conjunction with the question papers and the report on theexamination. ã CIE will not enter into discussions or correspondence in connection with these mark schemes.CIE is publishing the mark schemes for the May/June 2010 question papers for most IGCSE, GCEAdvanced Level and Advanced Subsidiary Level syllabuses and some Ordinary Level syllabuses. www.Xtr emePaper s.net  Page 2 Mark Scheme: Teachers’ version Syllabus Paper IGCSE – May/June 2010 0607 06 © UCLES 2010 M marks are given for a correct method.  A marks are given for an accurate answer following a correct method.  B marks are given for a correct statement or step.  D marks are given for a clear and appropriately accurate drawing.  P marks are given for accurate plotting of points.  E marks are given for correctly explaining or establishing a given result.  C marks are given for clear communication.  Abbreviations cao correct answer onlycso correct solution only   ft follow through   oe or equivalent   soi seen or implied   ww without working   www without wrong working   www.Xtr emePaper s.net  Page 3 Mark Scheme: Teachers’ version Syllabus Paper IGCSE – May/June 2010 0607 06 © UCLES 2010 Question Answer Mark Notes CommentsA1 (a)(b) 2811   B1B1Communication mark  possible for completemethod shown. 2 Prime Division Remainder Division RemainderDivision Remainder 3 2 3   ÷ 3 25 2 5   ÷ 5 2 3 5 ÷ 5   3 4 5   ÷ 5 47 2 7   ÷ 7 2 3 7 ÷ 7 3 4 7   ÷ 7 411 2 11   ÷ 11 2 3 11   ÷ 11 3 4 11   ÷ 11 43Deduct 12 for eacherror or omissionand round downB3Ignore extra entries 3 (a)(b) 11 717 811B1B1 4 (a)(b) 5 13   ÷ 13135(5 12   − 1) 131741B1B1B1 + B1B1 Accept 3, 5, 7, 13, 97, 241,257, 653 5  p 1 B1Accept (  p   − 1) + 1 or   p   − 1 + 1 6 Expression with  p prime and afactor of  a For example 10 5–1 – 1or 10 4 – 1Evaluation and comment that  p  is not a factor 2 B1R1Ignore extra expressions 7 7 24 – 1 = [ ( ) 212 7 – 1] = ( ) 1312 7 − – 1so 3 is prime factor 7 24 – 1 = [ ( ) 46 7  – 1] = ( ) 156 7 −  – 1so 5 is prime factor 7 24 – 1 = [ ( ) 122 7  – 1] = ( ) 1132 7 − – 1so 13 is prime factor 4 M1A1B1B1Apply to one correctanswer Apply to other correctanswers deducting one for each incorrectFurther prime factors are19,43,73,181,193,409,12011 C1 Communication seen inquestion 1 www.Xtr emePaper s.net  Page 4 Mark Scheme: Teachers’ version Syllabus Paper IGCSE – May/June 2010 0607 06 © UCLES 2010 Question Answer Mark Notes CommentsB1 (a) 20 1 B1 (b) 21 120 oe1 R1 Averaging speeds possible 2 41 1510 + oe2R1 15   ÷ 1.25 withtime in any formR1 for 15 and 411  shown in workingAccept 12 × 1.25 = 15 3 11.6 to 11.7(km/h) 2M1 51 1410 + oeIgnore extra methodsCommunication mark  possible but not for modelor  72840   4 (a) 10 2060160  x x + ×+ oe for numerator 2 B1 for numerator or denominator seen (b) Evidence of either multiplying topand bottom by 60 or commondenominators of 60 oe.1 R1 5 11.7 to 11.8(km/h) 1 B1 Communication mark (can be evidence of substitution) 6 2 G1 correct shapeG1 start at (0, 10) 7 26 or better 2 M1 Sketchshowingintersection of graphsM1600 + 20  x =13(60 +  x )Communication mark for complete correct methodshown or described.Reverse substitutionstatement does not gaincommunication www.Xtr emePaper s.net
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